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4x^2+76x-368=0
a = 4; b = 76; c = -368;
Δ = b2-4ac
Δ = 762-4·4·(-368)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-108}{2*4}=\frac{-184}{8} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+108}{2*4}=\frac{32}{8} =4 $
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